Web26 feb. 2024 · If x = 1 is the directrix of the parabola y2 = kx - 8, then k is: asked Mar 4, 2024 in Parabola by Harshwardhan (24.2k points) parabola 0 votes 1 answer (A) If the line x - 1 = 0 is the directrix of the parabola y^2 - kx + 8 = 0, then the value of k asked Nov 4, 2024 in Mathematics by RiteshBharti (54.0k points) parabola 0 votes 1 answer WebMultiply the numerator and denominator of the right side by y to obtain y0= y/(y +ycosy). Now use the identity y = x−siny to obtain y0= (x−siny +ycosy). (o) If x + y = arctany, then 1 + y0= y0/(1 + y2). Consequently, (1+y0)(1 +y2) = y0. This simplifies to 1+y2+y2y0= 0. 3.
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WebFirst of all, both lines are parallel so you can ignore the constant and the equation as both would still have the same slope. So you’d have 3x-4y and 3x+ky. And as they both have the same slope, that means that 3x-4y=3x+ky to find the value of k. Now, subtract 3x from both sides and you get -4y=ky. Divide by y and you get -4=k. Web21 feb. 2024 · Answer: x/ y = k Step-by-step explanation: It can also be written in forms like- x= ky y= x/ k ------------------- x/y = k (here k is constant ) Advertisement New questions … WebDatabar_Program_In_Basicd8—¢d8—¢BOOKMOBIQ) ˜ Á } ! $ $ $ð %Ä %à 8 ð4 ôT øp ý( ì *H .," 3¨$ 8 & ld( ¤l* CD, R . _ 0 lŒ2 q´4 yP6 ¼8 “Ä ... toys r us springfield ohio